Friday, November 22, 2013

Monash Cafeteria Questionnaire

Assignment 2 Monash Cafeteria Questionnaire 1. Statistics Q2 (1 to 5) NValid132 Missing0 specify2.40 median value2.00 Mode2 Q2 (1 to 5) FrequencypctValid Percent cumulative Percent Valid13325.025.025.0 24030.330.355.3 33627.327.382.6 41914.414.497.0 543.03.0100.0 essential132100.0100.0 Based on the output above, it is estimated that the current buy demeanor is that majority of school-age childs commonly take-away their purchases. This is demonstrated by unremarkably take-away response frequency of 30.3% and mode=2. analysis of division Q29 (1 to 7) Sum of Squ atomic consequence 18sdfMean SquareFSig. Between Groups5.21641.3041.077.371 Within Groups153.7541271.211 impart158.970131 To mark off whether the pattern should be stratified on the primer of the purchase doings of students (Q2), the above ANOVA results are analyzed. The ANOVA board is used to determine whether the overall satisfaction aim of student will differ depending on th e purchase behaviour root they belong to e.g. always take-away group. Since the Fstat value (1.077) is less(prenominal) than the Fcrit value (4,120,.05)=2.45, we reason that there is no difference amidst the overall satisfaction levels of students with diverse purchase behaviours. Therefore the try on should not be stratified based on this grouping. 2.
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The isotropy of people cheery with the service quality can be represented by the following equation: p ?=(X+2)/(n+4) = 91/136 = 0.6691 = 67% delight FrequencyPercentValid Percent cumulative Percent ValidSatisfie8967.467.467.4 U nsatisf4332.632.6100.0 Total132100.0100.0 ! Bound: p ?±2?(var(p ?)) NOTE: FPC is not required as the sample number (132) is less than 10% of the population number (approximately 40,000). p ?±2?((p ?(1-p ?))/(n+4)) p ?±2?((0.6691(1-0.6691))/136) B = 0.6691 ? 0.0807 This means we are 95% confident that the true proportion of students satisfied with...If you involve to hold fast a full essay, order it on our website: BestEssayCheap.com

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