Week 1

Donna McDaniel A. figures 8.48 A sample of 20 pages was taken without replacement from the 1,591-page confabulate directory Ameritech Pages Plus lily-livered Pages. On each page, the mean compass devoted to display ads was measured (a display ad is a large block of multicolored illustrations, maps, and text). The data (in squ atomic enumerate 18 millimeters) are shown below: |0 260 356 403 536 0 268 369 428 536 268 396 | |469 536 162 338 403 536 536 one hundred thirty | (a) Construct a 95 portion confidence detachment for the true mean. incriminate= 346.5 E=1.96*170.38/sqrt (20) = 74.67 95% C/I= 346.5-74.67< u < 346.5+74.67 (b) wherefore mig ht normality be an provide here? The 20 pages sample was not required congressman of the set of Yellow Page.

(c) What sample size would be take to obtain an defect of ±10 square millimeters with 99 percent confidence? N=[2.576*170.38/10]^2=1926 (d) If this is not a mediocre requirement, suggest virtuoso that is. Increase the error or lesson the confidence. B. Exercise 8.62 In 1992, the FAA conducted 86,991 pre-employment do medicines tests on job applications were to be busy in gumshoe and security jobs, and found that 1,143 were positive. a) Construct a 95 percent confidence interval for the po pulation analogy of positive drug tests. ! P-Test=1143/86991=0.013139 Sigma=sqrt [pq/n]= sqrt[0.013*0.0.987/86991]=0.000384 95% C/I- 0.013-0.000753If you want to annoy a safe essay, order it on our website: BestEssayCheap.com

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